Pg 634 (566) - Q18
In order for one integer to be as large as possible, the other 9
integers must be as small as possible. And since some of the integers
can be equal to each other, the smallest number that those 9 integers can
all be is 1. Thus, 9(1) + large # = 22, so that
the greatest possible value of the large # is 13, or choice B.