Pg 606 - Q14

Put these conditions into equations:
 x = (2/3) y  y = (3/5) z so:
    z = (5/3) y
x/z = ((2/3) y) / ((5/3) y)
 x/z = (2y / 3) * (3 / 5y)
 x/z = 6y / 15y = 6 / 15 = 2 / 5 (A)
 

Back to Answer Sheet