Pg 522 (454) - Q23
S = (N)(P) 1/xy = (0.0N)(0.00P) 1/xy = 0.0000(N)(P) = 0.0000S It might help to use test numbers. If N = 2 and P = 3, then: 1/xy = (0.02)(0.003) = 0.00006, and since S = (N)(P) = (2)(3) = 6, 1/xy = 0.0000S, which is A.
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