Pg 323 (335) - Q6
They want the area of the quadrilateral PQRS. Well, if you drop a right angle from Q down to the line SR, you have a square there that would be 7x4 or 28. Then you have a triangle on the other side that has a length of 3 and a height of 4(3x4)/2 would give you an area of 6. So, 6+28>30; therefore, your correct answer here is A.