Pg 286 (298) - Q20
 

Look for the consistencies here.  Both of these addition problems contain the values 7,4, and 5 which is equal to 16.  So, if we subtract 16 from 32, we can see that X+Y=16 in the first column.  And, if we subtract 16 from 52, we see that in the second column X+Z=36.  We are looking for the value of Z-Y.  We can get that because if we have X+Z=36 and subtract X+Y=16 from it, we find that Z-Y=20.

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